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5x^2=-9x+5
We move all terms to the left:
5x^2-(-9x+5)=0
We get rid of parentheses
5x^2+9x-5=0
a = 5; b = 9; c = -5;
Δ = b2-4ac
Δ = 92-4·5·(-5)
Δ = 181
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{181}}{2*5}=\frac{-9-\sqrt{181}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{181}}{2*5}=\frac{-9+\sqrt{181}}{10} $
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